What are N and M? | vedclass

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(B) The starting material is $2$-methylbutane. Chlorination of $2$-methylbutane $(C_5H_{12})$ with $Cl_2, h
u$ produces $4$ constitutional isomers of

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$6,4$

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(B) The starting material is $2$-methylbutane. Chlorination of $2$-methylbutane $(C_5H_{12})$ with $Cl_2, h
u$ produces $4$ constitutional isomers of $C_5H_{11}Cl$.These are: $1$-chloro-$2$-methylbutane,$2$-chloro-$2$-methylbutane,$2$-chloro-$3$-methylbutane,and $1$-chloro-$3$-methylbutane.Among these,$1$-chloro-$2$-methylbutane and $2$-chloro-$3$-methylbutane are chiral,meaning each exists as a pair of enantiomers ($d$ and $l$ forms).Thus,the total number of stereoisomers $(N)$ is $2 + 2 + 1 + 1 = 6$.Fractional distillation separates compounds based on their boiling points. Enantiomers have identical boiling points and cannot be separated by fractional distillation.Therefore,the number of fractions $(M)$ obtained is $4$ (corresponding to the $4$ constitutional isomers).

What are $N$ and $M$?

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